Mathematics and Origami
- OG → OG ; E → E
Result: EF - OI → OI ; F → F
Result: FH
13.6.2 CARDIOD
A BIT OF HISTORY
Fig. 1 shows the conchoid of a straight line named after Nichomedes. Curve c, in its
two branches, is determined by line r, pole P and equal segments like AB = AB ́.
The Pascal ́s limaçon (Fig. 2) is the conchoid of a circumference c (radius OP = r) with
respect to one of its points P, in such a way that always it is AB = AD < 2r. It also has two
branches.
The CARDIOID derives from the Pascal ́s limaçon, with this condition: AB = AD = 2r.
The curve is symmetric but has only one branch. Its shape reminds that of a heart (Fig. 3).
This Fig. 3 shows the rounded points of the cardioid at the extremities of its radius vec-
tors. Being
OP = r ; AB = AP = A ́B ́ = A ́B ́ ́ = 2r
and taking into account the right triangle PAA ́, the cardioid polar equation will be:
ρ= 2 rcosω+ 2 r
ρ= 2 r()cosω+ 1
We have drawn Fig. 3 by dividing the circumference with radius OA in 8 equal parts,
what means that, as P lies on the circumference, angles ω have these values:
22,5º; 45º; 67,5º; 90º; 112,5º; 135º; 157,5º and 180º
Let ́s see now how to make this construction by paper folding.
For that we shall draw (Fig. 4) a circumference with center O and radius 3r; then divide
it in 16 equal parts numbering them orderly.
Afterwards we fold the chords between points i → 2i in the circumference, as we ́ll see
later. Those folded chords will be the tangents to the cardioid, and this will be the envelope of
them.
P
B ́
B
A
c
r
c
P O
A
B
D
1 2