Jesús de la Peña Hernández
We have seen up to now that CAD allows us to draw Fig. 13 as well as Fig. 11. Then
we ́ll see the analytical procedure in case CAD would not be available.
Here are the data:- The side of the square = a.
- The distance between squares = h.
- The angle turned around each time = ω.
- Amount of turns and consequent upward moves given to the square = n. Obviously n
may be as great as we wish if the paper size can cope with it.
Let ́s look again to Fig. 10 in order to get the co-ordinates of points A, B, C, D
A ≡ (0,0,0) ; B ≡ (a,0,0)Ang. FAD =
245
2180
180 45π π
= +
−
− −22 sen
22 sen
22π π
aa
AD= =
= = +
2cos 45
2cos 2 senπ π
FA AD FAD a
= +
2sen 45
22 senπ π
DF a∆DFA = ∆BEC after transformation by the rotation π.
BE = FA ; CE = DF
= − +
2sen 45
22 senπ π
xC a a
= − +
2sen 45
21 2 senπ π
xC a
=− =− +
2cos 45
22 senπ π
yC BE azC=h
xD=yC
= +
2sen 45
22 senπ π
yD azD=hIts three sides define ∆ABD. Besides, calling p to its half-perimeter, its area will beS= p()( )( )p−a p−BD p−AD and therefore:
aS
h
2
́=Once the solid form of Fig. 11 is physically completed, we can check that the shrinkage
produced by the twist is equal to n()h ́.−h
We should recall that h ́ is the distance between horizontals in Fig. 13, and h is the same
distance taken in the space (sides DC and AB of Fig. 12, which cross each other): h ́ > h.