Jesús de la Peña Hernández
Fig. 4 will allow us to find the dihedral angle ε formed by two adjacent faces of a do-
decahedron, as well as its diameter. At left we have two pentagons like those in Fig. 3 and, as-
sociated with them, segments l, d, D and A. The value of the latter is:
A = a + r = 0,6881909 l + 0,8506508 l = 1,5388417 l
The figure at right is a hemispherical section of a dodecahedron; in it, D is the diagonal
of the great pentagon at left (see Fig. 3, Point 18.6.3). To draw that section we shall start by
∆YVW whose three sides are given. In it we get ε:
A
D
2 2
sen =
ε
; ε = 116,56505 º
The figure at right is symmetric with respect to XY; points V in it are vertices of the do-
decahedron. After all that we can deduce:
- the angle γ in the irregular hexagon with sides A, l:
180 (6 – 2 ) = 2 ε + 4 γ ; 121 , 71748
4
720 2 116 , 56505
=
− ×
γ =
- the proof that angle VWV is a right one:
Ang. VWV = 90
2
180 116 , 56505
121 , 71748
2
180
=
−
= −
−
−
ε
γ
A
l
B d C
D
d
d
4
A
D A
V
V
l
l
A
A
W
X
Z Y
O
2
d
2
l
d
3
D
A l B d C