MATHEMATICS AND ORIGAMI

(Dana P.) #1

Jesús de la Peña Hernández



  • Once Fig. 3 is folded we get a solid similar to that of Fig. 2; this is shown in Fig. 4 gather-
    ing to itself the cube of side l: This cube has obviously the same volume as the solid ob-
    tained from Fig. 3, and just half of the cube of side L.


SOLUTION 2

It is based on the orthogonal spiral of powers by H Huzita, as disclosed in Point
7.14.3. It is a matter of finding segment l such that its relation to another given segment

L will be =^32
l

L

. The process is as follows:



  • To set a co-ordinates system XY (Fig.1) fixing in it points O (origin) and F (final) at dis-
    tances d,a to the co-ordinates origin, respectively. Condition: a = d / 2.

  • To have available a pair of papers V,W (Fig. 2) with right angles.

  • By try and error (a maximum of three attempts will be enough) get (Fig. 3):


To lie a side of V on O in such a way that the vertex of its right angle will rest on axle
X. The other side of V will intersect axle Y in a point where we shall position the vertex of
right angle W.
One of the sides of W will lie on the latter side of V, and the other must pass through F.
If that would not be the case, try out a new configuration: it is easy because the process is
fast convergent. Eventually, we get an orthogonal broken line starting at O and ending at F.
It has its two right angles lying on both co-ordinate axles (Fig. 4).

F

O

a

1


d

V

W
X

Y 2


L

Y

F X

O

V

W

3 4


F a

Y

X
d

O

l

b
c
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