Jesús de la Peña Hernández
- Once Fig. 3 is folded we get a solid similar to that of Fig. 2; this is shown in Fig. 4 gather-
ing to itself the cube of side l: This cube has obviously the same volume as the solid ob-
tained from Fig. 3, and just half of the cube of side L.
SOLUTION 2
It is based on the orthogonal spiral of powers by H Huzita, as disclosed in Point
7.14.3. It is a matter of finding segment l such that its relation to another given segment
L will be =^32
l
L
. The process is as follows:
- To set a co-ordinates system XY (Fig.1) fixing in it points O (origin) and F (final) at dis-
tances d,a to the co-ordinates origin, respectively. Condition: a = d / 2. - To have available a pair of papers V,W (Fig. 2) with right angles.
- By try and error (a maximum of three attempts will be enough) get (Fig. 3):
To lie a side of V on O in such a way that the vertex of its right angle will rest on axle
X. The other side of V will intersect axle Y in a point where we shall position the vertex of
right angle W.
One of the sides of W will lie on the latter side of V, and the other must pass through F.
If that would not be the case, try out a new configuration: it is easy because the process is
fast convergent. Eventually, we get an orthogonal broken line starting at O and ending at F.
It has its two right angles lying on both co-ordinate axles (Fig. 4).
F
O
a
1
d
V
W
X
Y 2
L
Y
F X
O
V
W
3 4
F a
Y
X
d
O
l
b
c