MATHEMATICS AND ORIGAMI

Jesús de la Peña Hernández

0

2

1

WY^2 + 2 WY− = ; WY= 1

2

3

−

• VY=WYcosα=WY×LY=WY() 1 −VY ; VY() 1 +WY =WY

VY=

3

2

1 −

• Till now we have got segments BZ, WZ, WY, VY. The following stage would be to figure
  out the power of V with respect to the already mentioned circumference to carry on getting
  the successive stepped segments indicated above.


• At this moment we are prepared to get OB (its straight away value is 2 ), and also OD:

OD =

()

3

3

2

1 1 1

1

1 1

1

1

1

1 cos

1

sen

1

2 2 2 2 =





























− − −

=

− −

=

−

=

−

=

α α LY YV

• In a similar way we can get values of OF = 4, OH = 5 , etc.

6.8 HOW TO GET A RECTANGLE FROM AN IRREGULAR PIECE OF PAPER.
Solution in step 4.

6.9 STELLATE RECTANGLE

As we know, to get stellate polygons we must play properly with their diagonals. So we only

will have stellate polygons from the pentagon, forward.

Nevertheless, all polygons (triangles and quadrilaterals included) may take a stellate appear-

ance, not a flat one, but volumelike. In this respect they leave off to be polygons.

A very simple solution is to fold the angles ́ bisectors and the bisectors of the angles so ob-

tained. By means of this you can obtain beautiful shapes evoking architectonic forms (see Figs.

2 and 3 as an example).

d

d

e

f

d d

e

f

ee

f f

dd

(^12)
4 3