Jesús de la Peña Hernández
7.10 PARABOLA ASSOCIATED TO THE FOLDING OF A QUADRATIC EQUATION
Point 1.2.4 explained how in folding a point over a straight line, the crease became the tangent
to a parabola whose focus was the point to be moved and its directrix was the line which re-
ceives the point. That was already proved in Point 4 when demonstrating Haga ́s theorem.Now then, in fig 1 of Point 7.8 we have reproduced the same operation, so we can complete it
now by drawing the parabola with focus F ≡ A, directrix d, vertex V (midpoint of AO) and tan-
gent CE on point E whose abscissa is just 40.The equation of this parabola is:2
2 601
260
y x
×= + ;^2
1201
y= 30 + x (1)This equation has the same structure as (1) in Point 4: we may observe that its first term has a
length dimension (L) whereas the coefficient ofx^2 has L−^1 as dimension.Fig 1 of present Point 7.10 makes obvious that distances from E to F and from E to d are equal
because folding line EC is the symmetry axis. Eventually the result is the pair of tangents to a
parabola from point C.Fig 1 also shows:
∆AOE’ is similar to ∆HVC and thereforeVC2404060
= ;
340
VC=∆VHC = ∆EHG, then:EG = VC =
3403130
340
yE=EE'=E'G+GE= 30 + =i.e. it is
3130
E 40 ,Let ́s make now a translation of axes from the origin to D. Equation (1) will become:-40 0C(0,16.6)A(0,60)+40 XdFD EE'V H G1