MATHEMATICS AND ORIGAMI

(Dana P.) #1

Jesús de la Peña Hernández


3

1 4 ( 1 )
1

x
x

− −
=

;
3

1 4 ( 2 )
2

x
x

− −
=

In general: x^2 + 4x + 3 = 0

7.14.5 RESOLUTION OF THE COMPLETE EQUATION OF THIRD DEGREE (H. H)


First of all we ́ll recall Fig. 6 (Point 7.14) to show how the 3rd degree equation is behind it.
That figure is now completed with Fig. 1 of present Point 7.14.5

Let ́s get a t expression just dependent of: balls coordinates (0,0) and (l,m) ; a angle (whose
tangent is t); the configuration of billiards table (a,b):

t

b
bt+ty=a− ; m at lt
t

at b bt
= − +

− −
2

2

()( )l−at^3 + m+bt^2 −at+b= 0
This means that the orientation given to the ball in O in order to hit the other one placed at (l,m)
after rebounding orthogonally on both tablesides, is the only real root of the equation just ob-
tained. And that is so because the equation has a positive discriminant, according to drawing
scale.

It is important to insist that lines which receive points (0,0) and (l,m) along the folding opera-
tion, are parallel to their respective tablesides, and distant from them as much as the balls are
distant from said tablesides.

2


Y

I

X

X ́

x O

A
2 x 1

F

t=tgα

z

b
t=

b y

a z
t
+


=

a l

m y
t


=
(l,m)

O(0,0)

Y

(a,y) X

(a,b)^1
(z,b)
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