Mathematics and Origami2= i−^1 + i+^1
ia a
a ; 3 2 4 1 1 1 1 2 3
22 4
23
2a d a
a a a d a d a d
a = + =
+
=
+ + +
=
+
=Relation between term n and one of its precedent p, being i the number of terms in between the
two:
an=ap+d()i+ 1 ; a 4 =a 2 + 2 d
The sum of two equidistant terms from the extremes, is equal to the sum of these extremes:
a 1 +an=a 1 +i+an−i ; a 1 +a 4 =a 2 +a 3 (i = 1)
Sum of all of the terms of an arithmetic progression:na a
S n
2=^1 + ; S a a 4 2 a 2 a a a 2 ()a 3 d 4 a 6 d
2 1 4 1 1 1 1=^1 +^4 = + = + + + = +7.15.2 GEOMETRIC PROGRESSIONS
They are those in which each term is equal to its immediate precedent multiplied by a
constant r called ratio of the progression. Let ́s see first, one of the increasing type (r > 1). Fig.
2 in point 7.14.3 is one example. In it, the first term is a 1 = 1 and the ratio is a > 1.
If we wish that the first term be a 1 ≠ 1 (keeping the same ratio r = a) we would have to
build an orthogonal spiral parallel to the former one beginning with a 1. By so doing we get Fig.
1 of present point 7.15.2. In it, the value of each term is measured from O to the correspondent
ai. Through the similarity of the triangles shown we can also see that:4 15 r
aa
= ;
1 12 r
aa
=Here we have some properties that can be observed in Fig. 1:
Last term as a function of the first one and the ratio:
1
1
= n−
an ar ;
4
a 5 =a 4 r=a 3 r×r=a 2 r×r×r=a 1 r×r×r×r=a 1 r
Sum of the n from the first terms of a geometric progression as a function of the first, the last
and the ratio:11
−−
=
rar a
S n ; measuring on the figure, at a graphic scale, we have: (1)
a 5 = 2. 2458 ; a 4 = 2. 0215 ; a 3 = 1. 8196 ; a 2 = 1. 6378 ; a 1 = 1. 4742r= 1. 0751 ; 01 = 0. 9677
The value of r to be taken to the sum formula is 1.0751 / 0.9677 = 1.111aa 4a 1 1 o31
ra 2a 5