MATHEMATICS AND ORIGAMI

Mathematics and Origami

Solution 2 (very simple)

8.2 OBTENTION OF TRIANGLES
8.2.1 ISOSCELES RIGHT ANGLED TRIANGLES FROM A SQUARE

8.2.2 EQUILATERAL TRIANGLE FROM A SQUARE.

8.2.2.1 EQUAL SIDES OF TRIANGLE AND SQUARE.

Triangle ABC is the solution because AB = BC

If DC = 1

1

2

1

2

(^2) =






AE +
2
3
2
1
1
2
 =





AE= −
( 1 )
( 2 ) ( 1 )
( 2 )
( 1 )
( 2 ) ( 1 )
( 2 )
( 3 )
( 4 ) ( 3 )
( 4 )
✂
✂
✂
( 1 )
( 2 )
Triangles (1) and (2) are the solution.