MATHEMATICS AND ORIGAMI

Mathematics and Origami

Remarks:

• Piece C10 is not the triangle ABC in Fig. 1. In this, BC ≠ AD (being AD= 1). There is a
  small difference:

2 1. 06 1

4

3

CB= = ≠

That ́s why in the square over the great leg, the right angle of C10 does not lie on neither of

the vertices of the square. On the contrary, that happens on the square over the hypotenuse.

• It can be observed also that the sides of the squares are divided:
  ! in halves (great leg).
  ! in thirds (hypotenuse).


• The Pythagorean theorem approach can be presented also as a game with these alternatives:
  ! Make up two different squares with the five basic pieces. The two squares over both
  legs are the solution.
  ! Form one only square with the five pieces. The solution is the square over the hy-
  potenuse.
  ! With 2 sets of said five pieces (total of ten), build up one only square. Fig. 3 is the
  solution. In it you can also see 4 squares.

A6

B7

C10

D13

E12

I M

P N

KO

J J

O

I

G

H

I

O

L

F G

L

K O

1

22 2

(^11)
2
2
1
1
1
2
22
1
1
2
2
1
2
1
22
2
1 1
2
1
2
1
3