166 CHAPTER 3 Inequalities
Therefore, the maximum value of x+y is 3 (and the minimum
value ofx+yis−3).
Exercises.
- Given thatx+y= 1, x, y >0, find the minimum value of
1
x
+
1
y
.
- Given that
1
x
+
1
y
= 1, x, y >0, prove thatx+y≥4.
(Exercises 1 and 2 can be solved very simply by multiplying to-
gether
1
x
+
1
y
andx+yand using the result of Example 2.)
- Find the distance from the origin to the line with equation
x+ 3y= 6. - Given that
x
y
+y= 1 find the minimum value of
x+y, x, y >0.
- Find the largest value of a so that the parabola with equation
y=a−x^2 is tangent to the circle with graphx^2 +y^2 = 4. Go on
to argue that this value ofais the maximum of the functionx^2 +y
given thatx^2 +y^2 = 4. - Letf(x) =ax^2 +bx+c, and so the derivative is f′(x) = 2ax+b.
Denote byR(f) the determinant
R(f) = det
a b c
2 a b 0
0 2a b
.
Show thatR(f) =−aD(f),whereD=D(f) is the discriminant
off(x).