172 CHAPTER 3 Inequalities
Example. Compute the minimum value of the function
f(x) =
1
x^2
+x, x >0.
Solution. The minimum value will occur where the line y = c is
tangent to the graph of y = f(x). We may write the equation
f(x) =cin the form of a cubic polynomial inx:
x^3 −cx^2 + 1 = 0.
As the tangent indicates a multiple zero, we must have ∆ = 0. As
a= 1, b=−c, c= 0, d= 1, we get the equation 4c^3 −27 = 0,
which implies that the minimum value is given byc=
3
√ 34 (which
can be verified by standard calculus techniques).
Now try these:
Exercises.
- Compute the minimum of the function
h(x) =
1
x
+x^2 , x >0.
- Compute the minimum of 2y−xgiven that
x^3 −x^2 y+ 1 = 0. - Compute the maximum value ofy+x^2 given that
x^3 −xy+ 2 = 0.