184 CHAPTER 3 Inequalities
y=3/x+x
y=1/x
3
y=x
3
y=m
We let m be the minimum value of f(x) and note that the graph of
y=mmust be tangent to the graph ofy=
3
x
+x^3. This is equivalent
to saying that the solution of 3 +x^4 =mxis a multiple root, forcing the
discriminant of the quartic polynomialq(x) =x^4 −mx+ 3 to be zero.
That is to say, we need to find that value ofmmaking the discriminant
equal to 0. From the above, we have that
0 = ∆(q) = 4^433 − 33 m^4 = 0⇒m= 4.
In other words, the minimum value ofq(x) on the interval (0,∞) is 4.
(The reader should check that the same result is obtained via differential
calculus.)