SECTION 1.2 Triangle Geometry 21
[DXB], so
GX
XI
ID
DH
HB
BG
=−1.
[AY F], so
GA
AI
IY
Y H
HF
FG
=−1.
[CZE] (etc.)
[ABC] (etc.)
[DEF] (etc)
Step 3. Multiply the above five factorizations of −1, cancelling
out all like terms!
- This time, let the hexagram be in-
scribed in a circle, as indicated to
the right. By producing edges [AC]
and [FD] to a common point R
and considering the triangle 4 PQR
prove Pascal’s theorem, namely
that points X, Y, and Z are co-
linear. (Proceed as in the proof
of Pappus’ theorem: consider the
transversals [BXF], [AY D], and
[CZE], multiplying together the
factorizations of−1 which each pro-
duces.) - A straight line meets the sides [PQ], [QR],[RS],and [SP] of the
quadrilateralPQRS at the pointsU, V, W,andX, respectively.
Use Menelaus’ theorem to show that