8.3 Volume Integrals, Gauss 131
As a more specific example, a half-sphere with radiusR, located above thex–y-
plane, is chosen. When, furthermore, the functionfdoes not depend on the angleφ,
the volume integral reduces to
V = 2 π
∫R
0
r^2 dr
∫ 1
0
dζ f(r(r, ζ )). (8.53)
The minus sign occurring in (8.52) is taken care of by an exchange of the integration
limits,θ=0 andπ/2 correspond toζ=1 andζ=0.
Forf=1thevolumeV=( 2 / 3 )πR^3 of the half-sphere is obtained.
8.3.2 Application: Mass Density, Center of Mass
The macroscopic description of matter, be it a gas, a liquid, or a solid, is based on
the mass densityρ=ρ(r). Its microscopic interpretation, for a substance composed
ofNparticles with the massm, is provided by
ρ(r)d^3 r=mdN(r), (8.54)
where dN(r)is the number of particles found within a small volume element d^3 r,
located at the positionr. Alternatively, and even more general, the mass density
of a substance composed of particles with massesmi, located at positionsri, with
i= 1 , 2 ,...,N, is given by
ρ(r)=
∑N
i= 1
miδ(r−ri). (8.55)
Hereδ(r)is the three dimensional delta-distribution functionδ(r), with the property
∫
δ(r−s)f(r)d^3 r=f(s), (8.56)
which applies when the functionfis single valued at the positions. The integrals of
both expressions forρ, over a volumeV, yield the massMVof the substance within
this volume,
MV=
∫
V
ρ(r)d^3 r. (8.57)