Introduction to Electric Circuits

(Michael S) #1
174 Transient analysis

i.e. it is the steady state value (I) of the current, so we have finally
i = 111 - exp (-Rt/L)] (8.2)

The time constant of an RL circuit
From Equation (8.2) we note that when t = L/R seconds,
i= 111 - exp (-1)] - 0.632 1 (8.3)
L/R is called the time constant of the circuit. Its symbol is ~-and it is measured
in seconds:
~"- L/R (8.4)
From Equation (8.3) we see that after a time equal to the time constant
following the sudden application of a step function, the current will have
reached 63.2 per cent of its steady state value. After a time equal to five time
constants (5r) the current will have reached [1 - exp (-5)] - 0.993 or 99.3 per
cent of its steady state value. Since mathematically the current can never reach
I we say that to all intents and purposes it has done so after 5~-.
The voltage across the resistor is VR = iR = I[1- exp (-Rt/L)]R and,
since IR = V,
V R = VII - exp (-Rt/L)] (8.5)
The voltage across the inductor is vL = V- VR = V- V[1 - exp (-Rt/L)], so
VL = V exp (-Rt/L) (8.6)
Equation (8.2) describes an exponential growth of current, Equation (8.5)
describes an exponential growth of voltage and Equation (8.6) describes an
exponential decay of voltage. The graphs of these are shown in Figs 8.3 and
8.4.

0.6321

f I
I
z 5z
Figure 8.3

VIr--

0.368V

VR

~t 0 ~ 5x ~--
Figure 8.4

The rate of change of current is obtained by differentiating Equation (8.2).
Thus, remembering that I = V/R


di/dt = (V/R)(R/L) exp (-Rt/L)
= (V/L) exp (-Rt/L) (8.7)

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