3.8 The maximum power transfer theorem 55Ro
A
ILREFigure 3.28
load resistor R L is given by PL -- /L2RL 9 But I L -- Eo/(Ro + RL) SO that
PL = Eo2RL/(Ro + RL) 2 (3.1.4)
As RE varies, with E0 and R0 being constant, this will be a maximum (or a
minimum) when dPc/dRc = 0. Using the technique for differentiating a
quotient we get
dPL/dRL = {(Ro + RL)2Eo 2- Eo2RL[2(Ro + RL)]J/(Ro + RL) 4This will be zero when the numerator is zero, i.e. when
(R0 + RL)ZEo 2: 2Eo2RL(Ro + RE)
Ro + RL = 2RL
R0 = RL (3.15)
This can be confirmed as a maximum, rather than a minimum, by showing that
d2pL/dRL 2 is negative.
The power delivered to the load is therefore a maximum when the resistance
of the load is equal to the internal resistance of the source or network, and this
is called the maximum power transferred theorem. The actual value of the
maximum power transferred is obtained by putting RE = R0 into the equation
for Pc. This gives
emax-- Eo2RL//(RL + RE) 2= Eo2RL//(2RL) 2
emax-- Eo2/4RL 9 (3.16)Example 3.8
For the circuit of Fig. 3.18 (Example 3.6) determine:
(1) the value of the load resistor, r, which would give the maximum power
transfer; and(2) the maximum power transferred to the load.
Solution1 Using the Thevenin equivalent circuit of Fig. 3.19, the maximum power