C
O OHH 2 O
87%
no anolH 2 CH 3 C CH 3 H 3 CH 2 C CHCH 3NaBH 42-Buta ne 2-But- The key step in the reduction of a carbonyl compound by either LiAlH 4 or NaBH 4
1)Mechanism for the Reaction
is the transfer of a hydride ion from the metal to the carbonyl carbon.
The hydride ion acts as a nucleophile.A
Reduction of Aldehydes and Ketones by Hydride Transfer
BH 3 H H OHRR'C
Oδ+ δ−
+
R'H C O −RR'H C O HHydride transfer Alkoxide ion AlcoholR(^)
- NaBH 4 is a less powerful reducing agent than LiAlH 4.
- LiAlH 4 reduces acids, esters, aldehydes, and ketones.
- NaBH 4 reduces only aldehydes and ketones.
C O− C C CO
R OR'O
R HO
<<R' RO
R <ReducedbyLiAlH 4Ease of reductioned by NaBH 4- LiAlH 4 reacts violently with water reductions with LiAlH 4 must be carried
1) over to decompose excessRecuc⇒
out in anhydrous solutions, usually in anhydrous ether.
Ethyl acetate is added cautiously after the reaction is
LiAlH 4 , then water is added to decompose the aluminum complex.