(^)
3) The overall result of second step is the reduction of HCrO 4 – to HCrO 3 – , a two
electron (2 e–) change in the oxidation state of chromium, from Cr(VI) to Cr(IV).
4) At the same time the alcohol undergoes a 2 e– oxidation to the ketone.
5) The remaining steps of the mechanism are complicated which involve further
oxidations (and disproportionations), ultimately, converting Cr(IV) compounds
to Cr3+ ions.
- The aldehydes initially formed are easily oxidized to carboxylic acids in aqueous
solutions.
- The aldehyde initially formed from a 1° alcohol reacts with water to form an
aldehyde hydrate. - The aldehyde hydrate can then react with HCrO 4 – (and H+) to form a chromate
ester, and this can then be oxidized to the carboxylic acid. - In the absence of water (i.e., using PCC in CH 2 Cl 2 ), the aldehyde hydrate does
not form ⇒ further oxidation does not happen.
Aldehyde hydrateCarboxylic acidHCR
O O
HH H
HOCR O−
+ HHCrO 4 −
OHO H
C
HRO CrO H
C
HR
OOOH
O
HHOCR
O
H+ HCrO 3 − + H 3 O+, H+- The chromate ester from 3° alcohols does not bear a hydrogen that can be
eliminated, and therefore no oxidation takes place.