bei48482_FM

(Barry) #1

226 Chapter Six


EXERCISES


To strive, to seek, to find, and not to yield. —Alfred, Lord Tennyson

6.3 Quantum Numbers


  1. Why is it natural that three quantum numbers are needed to
    describe an atomic electron (apart from electron spin)?

  2. Show that



20 () (3 cos^2 1)

is a solution of Eq. (6.13) and that it is normalized.


  1. Show that


R 10 (r) er^ a^0

is a solution of Eq. (6.14) and that it is normalized.


  1. Show that


R 21 (r) er^2 a^0

is a solution of Eq. (6.14) and that it is normalized.


  1. In Exercise 12 of Chap. 5 it was stated that an important
    property of the eigenfunctions of a system is that they are
    orthogonal to one another, which means that
    
    
    *nmdV 0 nm


r
a 0
^1
2  6 a 03 2

^2
a 03 2

 10 

4

Verify that this is true for the azimuthal wave functions (^) mlof
the hydrogen atom by calculating
2 
0
*ml (^) mld
for mlml.



  1. The azimuthal wave function for the hydrogen atom is
    ()Aeiml
    Show that the value of the normalization constant Ais 1  2 
    by integrating | |^2 over all angles from 0 to 2.


6.4 Principal Quantum Number

6.5 Orbital Quantum Number


  1. Compare the angular momentum of a ground-state electron in
    the Bohr model of the hydrogen atom with its value in the
    quantum theory.

  2. (a) What is Schrödinger’s equation for a particle of mass m
    that is constrained to move in a circle of radius R, so that 
    depends only on ? (b) Solve this equation for and evaluate
    the normalization constant. (Hint: Review the solution of
    Schrödinger’s equation for the hydrogen atom.) (c) Find the
    possible energies of the particle. (d) Find the possible angular
    momenta of the particle.


Example 6.4
A sample of a certain element is placed in a 0.300-T magnetic field and suitably excited. How
far apart are the Zeeman components of the 450-nm spectral line of this element?
Solution
The separation of the Zeeman components is



Since c , dc d ^2 , and so, disregarding the minus sign,

 



2.83 10 ^12 m0.00283 nm

(1.60^10 ^19 C)(0.300 T)(4.50^10 ^7 m)^2
(4)(9.11 10 ^31 kg)(3.00 108 m/s)

eB 2

4 mc

2 

c

eB

4 m

bei48482_ch06 1/23/02 8:16 AM Page 226

Free download pdf