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Inorganic and Applied Chemistry
^
(^952)
2 14 2
- 010
- 010
- 0 10
A
OH HA
M
M
M
K HA
K
K A
a
w
b
Once again we look at the initial and end concentrations:
[A2-] 0 = 3.3 · 10-2 M
[HA-] 0 = 0 M
[OH-] 0 0 M (the autoprotolysis of water is neglected)
And the end concentrations are thereby:
[A2-] = (3.3 · 10-2 – x) M
[HA-] = x M
[OH-] x M
Hereby we arrive at the following equation:
x M
x
K M x x
b
4
2
(^55). 7 10 - 310
- 010
(
The concentration of OH- ions is 5.7 · 10-4 M which is why the concentration of H 3 O+ ions is found as:
M
M
HO OH K HO M
w
11
4
14 2
(^335). 710 1.^710 - (^010)
(
why pH becomes:
pH log 1. 710
11 10. 8
After the second point of equivalence the solution only contains a solution of the weak base A2- as well as
the strong base OH- ions from the added NaOH in excess. In such a case we will as earlier neglect the
contribution from A2- to pH and thereafter calculate pH as if there were only the strong base OH- present
in the solution.
5.6.2 Colour indicators for acid/base titration
Apart from using a pH meter to determine the pH value in a given solution a colour indicator is often added
to a given solution that is to be titrated. Such a colour indicator changes colour when the point of equivalence
is reached. A typical colour indicator is a complex molecule, often being actually a weak acid itself. In
Acids and bases