Figure 3: Superconducting ring with a capacitor parallel to a Josephson junction3.1.2 Quantization of the Magnetic Flux
The next example is the quantization of magnetic flux in a superconducting ring with a Josephson
junction and a capacitor parallel to it (see fig. 3). The equivalent to the equations of motion is here
the equation for current conservation:
CΦ + ̈ ICsin( 2 πΦ
Φ 0)
=−Φ−Φe
L 1What are the terms of this equation? The chargeQin the capacitor with capacityCist given by
Q=C·VwithV as the voltage applied. Derivate this equation after the timetgives the currentI:
Q ̇=I=C·V ̇With Faraday’s lawΦ = ̇ V (Φas the magnetic flux) this gives the first term for the current through
the capacitor
I=C·Φ ̈.The currentIin a Josephson junction is given by
I=Ic·sin(
2 πΦ
Φ 0)with the flux quantumΦ 0 , which is the second term. The third term comes from the relationship
between the fluxΦin an inductor with inductivityL 1 and a currentI:
Φ =L 1 ·IWith the applied fluxΦeand the flux in the ring this results in
I=
Φ−Φe
L 1,
which is the third term.
In this example it isn’t as easy as before to construct a Lagrangian. But luckily we are quite smart
and so the right Lagrangian is
L(Φ,Φ) = ̇CΦ ̇^2
2
−
(Φ−Φe)^2
2 L 1+Ejcos(
2 πΦ
Φ 0)
.