16.5.2 TheJosephsonEffect
We regard two superconductors separated by a thin insulating layer. In the followingψ 1 denotes
the probability amplitude on one side andψ 2 on the other side of the insulator. We write the time
dependentSchrödingerequations for this problem
i~∂
∂tψ 1 =~Tψ 2 , i~∂
∂tψ 2 =~Tψ 1 , (336)where~T is the interaction rate between the electron pairs, referred to as electron pair coupling.
Similar to Sec. 16.4.4 we writeψiasψi=
√
niexp(iθi). We now insert these expressions in the above
equations, (336) and multiply the resulting equations withψ∗ 1 andψ∗ 2 , respectively. We obtain
1
2∂
∂t
n 1 +in 1∂
∂t
θ 1 =−iT√
n 1 n 2 exp(iδ) (337)and
1
2∂
∂t
n 2 +in 2∂
∂t
θ 2 =−iT√
n 1 n 2 exp(iδ) (338)whereδ=θ 2 −θ 1. We now equate the real and imaginary parts in order to obtain
∂
∂t
n 1 = 2T√
n 1 n 2 sin(δ)∂
∂t
n 2 =− 2 T√
n 1 n 2 sin(δ), (339)and
∂
∂t
θ 1 =−T√n
1
n 2
cos(δ),∂
∂t
θ 2 =−T√n
2
n 1
cos(δ). (340)In particular forn 1 ≈n 2 , we have
∂
∂t
(θ 2 −θ 1 ) = 0, (341)and
∂
∂t(n 2 +n 1 ) = 0. (342)Since the current is proportional to∂t∂n 2 we obtain
J=J 0 sin(θ 2 −θ 1 ) (343)whereJ 0 serves as a proportionality constant. Note thatJ 0 is also proportional toT. Hence, we
obtained that there is a current flow according to the phase differenceδeven if no external field is
applied. This is the dcJosephsoneffect.
We now regard the case of an applied potentialV. The equations (336) apply:
i~∂
∂t
ψ 1 =~Tψ 2 −qV ψ 1 , i~∂
∂t
ψ 2 =~Tψ 1 +qV ψ 2. (344)