Analysis of this equation demonstrates that the velocity vector v is directed along
the tangent vector at any time t and has the magnitude given by v = dsdt which
represents the speed of the particle.
The derivative of the velocity vector with respect to time tis the acceleration
and
a =dv
dt
=ˆetdv
dt
+d
ˆet
dt
v.
From the Frenet-Serret formula and using chain rule differentiation, it can be shown
that the time rate of change of the unit tangent vector is
dˆet
dt
=dˆet
ds
ds
dt
=v
ρ
ˆen.
Substituting this result into the acceleration vector gives
a =dv
dt
ˆet+v
2
ρ
ˆen.
The resulting acceleration vector lies in the osculating plane. The tangential compo-
nent of the acceleration is given by dvdt ,and the normal component of the acceleration
is given by v
2
ρ.
Surfaces
A surface can be defined
(i) Explicitly z=f(x, y )
(ii) Implicitly F(x, y, z ) = 0
(iii) Parametrically x=x(u, v ), y =y(u, v ), z =z(u, v )
(iv) As a vector r =r (u, v ) = x(u, v )ˆe 1 +y(u, v )ˆe 2 +z(u, v )ˆe 3
or r =r (x, y ) = xˆe 1 +yˆe 2 +f(x, y )ˆe 3
(v) By rotating a curve about a line.
Here again it should be noted that the parametric representation of a surface is not
unique.