Begin2.DVI

(Ben Green) #1
This is an equation where the variables can be separated and then an integration

produces another independent family of surfaces

μ 2 (x, y, z ) = x

2
2

−y

2
2

=c 2.

Hence the field lines are the intersection of the family of cylindrical surfaces, defined

by hyperbola with rulings parallel to the z-axis, with the family of planes x+y−c 1 z= 0.

Method of Tangents.


Observe that if the field lines are defined as the intersection of two families of

surfaces

μ 1 (x, y, z) = c 1 and μ 2 (x, y, z ) = c 2 ,

then by differentiation one obtains

∂μ 1
∂x

dx +∂μ^1
∂y

dy +∂μ^1
∂z

dz = grad μ 1 ·dr = 0

In a similar fashion one can show

∂μ 2
∂x dx +

∂μ 2
∂y dy +

∂μ 2
∂z dz = grad μ^2 ·dr = 0.

Note that at a point (x, y, z )on a curve of intersection of two surfaces μ 1 =c 1 and

μ 2 =c 2 ,the tangential direction dr =dx ˆe 1 +dy ˆe 2 +dz ˆe 3 is the same as the direction

of the field line at that point. Therefore dr must be proportional to F . At the

common point (x, y, z )on both surfaces the gradient vectors grad μ 1 and grad μ 2 are

perpendicular to the surfaces μ 1 =c 1 and μ 2 =c 2 respectively. These vectors must

therefore be perpendicular to the vector field F at this common point. Consequently,

one can write grad μ 1 ·F = 0 or

∂μ 1
∂x

F 1 +∂μ^1
∂y

F 2 +∂μ^1
∂z

F 3 = 0

and similarly grad μ 2 ·F= 0 or

∂μ 2
∂x F^1 +

∂μ 2
∂y F^2 +

∂μ 2
∂z F^3 = 0.

These equations are the basis for the method of tangents. One tries to find, by using

a trial and error method, two vector functions V = grad μ 1 and W = grad μ 2 such that

V ·F = 0 and W ·F= 0.Then the equations

V ·dr = grad μ 1 ·dr = 0 and W ·dr = grad μ 2 ·dr = 0

are exact differential equations which are easily integrated. From these integrations

one finds two independent family of surfaces μ 1 =c 1 and μ 2 =c 2.
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