Begin2.DVI

(Ben Green) #1
there will be very little difference in calculation of the standard deviation from either

definition. To convert the standard deviation S, calculated using equation (11.13)

one need only multiply Sby


n
n− 1

to obtain the value sas specified by equation

(11.12).

The sample variance given by equation (11.12) requires that one first calculate

X, then one must calculate all the terms Xj−X. All this preliminary calculation

introduces roundoff errors into the final result. The sample variance can be cal-

culated using a short cut method of computing without having to do preliminary

calculations. The short cut method is derived using the expansion

(Xj−X)^2 =Xj^2 − 2 XjX+X^2

and substituting it into equation (11.12). A summation of terms gives

∑n

j=1

(Xj−X)^2 =

∑n

j=1

Xj^2 − 2 X

∑n

j=1

Xj+X^2

∑n

j=1

(1)

The substitution X=^1

n

∑n

j=1

Xjand using

∑n

j=1

(1) = n, gives the result

∑n

j=1

(Xj−X)^2 =

∑n

j=1

Xj^2 − 21
n

∑n

j=1

Xj

∑n

j=1

Xj+


^1
n

∑n

j=1

Xj



2
n

=

∑n

j=1

Xj^2 −^2
n



∑n

j=1

Xj



2
+^1
n



∑n

j=1

Xn



2

=

∑n

j=1

Xj^2 −^1
n



∑n

j=1

Xj



2

This produces the shortcut formula for the sample variance

s^2 =n−^11



∑n

j=1

Xj^2 −n^1



∑n

j=1

Xj



2 
 (11 .14)

If X 1 ,... , X mare msample values occurring with frequencies f ̃ 1 ,... , f ̃m, the equa-

tion (11.14) can be expressed in the form

s^2 =n−^11



∑m

j=1

Xjf ̃j−^1 n



∑m

j=1

Xjf ̃j



2 
 (11 .15)
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