It therefore remains to show that v 1 =v. The geometry of figure 6-14, provides an
aid in demonstrating that the vectors r 1 and r are related by the vector equation
r 1 =A+r,
where A is a vector from the origin of one system to the origin of the other system
and lying along the axis of rotation and in the same direction as ω.These results
demonstrate that ω×A= 0 and
dr 1
dt
=v 1 =ω×r 1 =ω×(A+r ) = ω×A+ω×r =ω×r =v =dr
dt
,
Here the distributive law for cross products has been employed and the fact that
both ωand A have the same direction produced a cross product of zero.
Let B denote any vector connecting two fixed
points within a rigid body which is rotating about
a line with angular velocity ω. Let r 1 denote a
vector to the terminus of B and let r 2 denote a
vector to the origin of B, as measured from some
origin on the axis of rotation. One can then write
dr 1
dt
=ω×r 1 and dr^2
dt
=ω×r 2
Observe that by vector addition r 2 +B =r 1 so that
dB
dt =
dr 1
dt −
dr 2
dt =ω×r^1 −ω×r^2 =ω×(r^1 −r^2 ) = ω×
B
Therefore one can state that in general, if B is any fixed vector lying within a rigid
body which is rotating, then with respect to any origin on the axis of rotation, one
can state that
dB
dt
=ω×B (6 .59)