666 | Thermodynamics
Analysis The change in internal energy of any simple compressible system
in any phase during any process can be determined from Eq. 12–30:
The van der Waals equation of state is
Then
Thus,
Substituting gives
Integrating yields
which is the desired relation.
u 2 u 1 c 11 T 2 T 12
c 2
2
1 T^22 T 122 aa
1
v 1
1
v 2
b
u 2 u 1
T 2
T 1
1 c 1 c 2 T 2 dT
v 2
v 1
a
v^2
dv
Ta
0 P
0 T
b
v
P
RT
vb
RT
vb
a
v^2
a
v^2
a
0 P
0 T
b
v
R
vb
P
RT
vb
a
v^2
u 2 u 1
T 2
T 1
cv dT
v 2
v 1
cTa
0 P
0 T
b
v
Pd dv
EXAMPLE 12–8 Internal Energy as a Function of Temperature Alone
Show that the internal energy of (a) an ideal gas and (b) an incompressible
substance is a function of temperature only, uu(T).
Solution It is to be shown that uu(T) for ideal gases and incompressible
substances.
Analysis The differential change in the internal energy of a general simple
compressible system is given by Eq. 12–29 as
(a) For an ideal gas PvRT. Then
Thus,
To complete the proof, we need to show that cvis not a function of veither.
This is done with the help of Eq. 12–42:
a
0 cv
0 v
b
T
Ta
02 P
0 T^2
b
v
ducv dT
Ta
0 P
0 T
b
v
PTa
R
v
bPPP 0
ducv dTcTa
0 P
0 T
b
v
Pd dv