17–4 ■ ISENTROPIC FLOW THROUGH NOZZLES
Converging or converging–diverging nozzles are found in many engineering
applications including steam and gas turbines, aircraft and spacecraft
propulsion systems, and even industrial blasting nozzles and torch nozzles.
In this section we consider the effects of back pressure(i.e., the pressure
applied at the nozzle discharge region) on the exit velocity, the mass flow
rate, and the pressure distribution along the nozzle.
Converging Nozzles
Consider the subsonic flow through a converging nozzle as shown in
Fig. 17–20. The nozzle inlet is attached to a reservoir at pressure Prand
temperature Tr. The reservoir is sufficiently large so that the nozzle inlet
velocity is negligible. Since the fluid velocity in the reservoir is zero and
the flow through the nozzle is approximated as isentropic, the stagnation
pressure and stagnation temperature of the fluid at any cross section
through the nozzle are equal to the reservoir pressure and temperature,
respectively.
836 | Thermodynamics
EXAMPLE 17–4 Critical Temperature and Pressure in Gas Flow
Calculate the critical pressure and temperature of carbon dioxide for the flow
conditions described in Example 17–3 (Fig. 17–19).
Solution For the flow discussed in Example 17–3, the critical pressure and
temperature are to be calculated.
Assumptions 1 The flow is steady, adiabatic, and one-dimensional. 2 Carbon
dioxide is an ideal gas with constant specific heats.
Properties The specific heat ratio of carbon dioxide at room temperature is
k1.289 (Table A–2a).
Analysis The ratios of critical to stagnation temperature and pressure are
determined to be
Noting that the stagnation temperature and pressure are, from Example
17–3, T 0 473 K and P 0 1400 kPa, we see that the critical temperature
and pressure in this case are
Discussion Note that these values agree with those listed in Table 17–1, as
expected. Also, property values other than these at the throat would indicate
that the flow is not critical, and the Mach number is not unity.
P*0.5477P 0 1 0.5477 21 1400 kPa 2 767 kPa
T*0.8737T 0 1 0.8737 21 473 K 2 413 K
P*
P 0
a
2
k 1
b
k>1k 12
a
2
1.289 1
b
1.289>11.289 12
0.5477
T*
T 0
2
k 1
2
1.289 1
0.8737
T*
P*
= 473 K
= 1.4 MPa
CO 2
T 0
P 0
FIGURE 17–19
Schematic for Example 17–4.
x
Lowest exit
pressure
P/P 0
Reservoir P
e
x
P*
Vr= 0
0
1
P 0
Pb =P*
Pb <P*
5 Pb =0
4
3
2
1
Pb >P*
Pb =P 0
Pb
(Back
pressure)
Pr = P 0
Tr = T 0
FIGURE 17–20
The effect of back pressure on the
pressure distribution along a
converging nozzle.
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