a state function, and the entropy change of an ideal gas with constant
specific heats during a change of state from 1 to 2 is given by
(17–55)
The entropy of a fluid may increase or decrease during Rayleigh flow,
depending on the direction of heat transfer.
Equation of stateNoting that PrRT, the properties P,r, and Tof an
ideal gas at states 1 and 2 are related to each other by
(17–56)
Consider a gas with known properties R,k, and cp. For a specified inlet
state 1, the inlet properties P 1 ,T 1 ,r 1 ,V 1 , and s 1 are known. The five exit
properties P 2 ,T 2 ,r 2 ,V 2 , and s 2 can be determined from the five equations
17–50, 17–51, 17–53, 17–55, and 17–56 for any specified value of heat
transfer q. When the velocity and temperature are known, the Mach number
can be determined from.
Obviously there is an infinite number of possible downstream states 2
corresponding to a given upstream state 1. A practical way of determining
these downstream states is to assume various values of T 2 , and calculate all
other properties as well as the heat transfer qfor each assumed T 2 from the
Eqs. 17–50 through 17–56. Plotting the results on a T-sdiagram gives a
curve passing through the specified inlet state, as shown in Fig. 17–52. The
plot of Rayleigh flow on a T-sdiagram is called the Rayleigh line,and sev-
eral important observations can be made from this plot and the results of the
calculations:
1.All the states that satisfy the conservation of mass, momentum, and
energy equations as well as the property relations are on the Rayleigh
line. Therefore, for a given initial state, the fluid cannot exist at any
downstream state outside the Rayleigh line on a T-sdiagram. In fact,
the Rayleigh line is the locus of all physically attainable downstream
states corresponding to an initial state.
2.Entropy increases with heat gain, and thus we proceed to the right on
the Rayleigh line as heat is transferred to the fluid. The Mach number is
Ma 1 at point a, which is the point of maximum entropy (see Exam-
ple 17–13 for proof). The states on the upper arm of the Rayleigh line
above point aare subsonic, and the states on the lower arm below point
aare supersonic. Therefore, a process proceeds to the right on the Ray-
leigh line with heat addition and to the left with heat rejection regard-
less of the initial value of the Mach number.
3.Heating increases the Mach number for subsonic flow, but decreases it
for supersonic flow. The flow Mach number approaches Ma 1 in both
cases (from 0 in subsonic flow and from ∞in supersonic flow) during
heating.
4.It is clear from the energy balance q cp(T 02 T 01 ) that heating
increases the stagnation temperature T 0 for both subsonic and super-
sonic flows, and cooling decreases it. (The maximum value of T 0 occurs
at Ma 1.) This is also the case for the thermodynamic temperature T
MaV>cV> 1 kRT
P 1
r 1 T 1
P 2
r 2 T 2
s 2 s 1 cp ln
T 2
T 1
R ln
P 2
P 1
862 | Thermodynamics
Mab = 1/ k
Maa = 1
a
a
b
Ma < 1
Ma > 1
Cooling
(Ma S 0)
Cooling
(Ma S )
Heating
(Ma S 1)
Heating
(Ma S 1)
Tmax
smax
s
T
FIGURE 17–52
T-sdiagram for flow in a constant-area
duct with heat transfer and negligible
friction (Rayleigh flow).
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