Introduction to SAT II Physics

(Darren Dugan) #1

The torque acting on the pendulum is the product of the force acting perpendicular to the radius of the
pendulum and the radius,. A free-body diagram of the pendulum shows us that the force acting


perpendicular to the radius is.


Since torque is the product of and


R

, the torque is.


  1. D


The seesaw is in equilibrium when the net torque acting on it is zero. Since both objects are exerting a force


perpendicular to the seesaw, the torque is equal to. The 3 kg mass exerts a torque of

N · m in the clockwise direction. The second mass exerts a torque in the counterclockwise

direction. If we know this torque also has a magnitude of 30g N · m, we can solve for m:


  1. E


The rotational equivalent of Newton’s Second Law states that. We are told that N ·


m and (^) I =^1 / 2 MR^2 , so now we can solve for :



  1. B

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