FORCE, MASS AND ACCELERATION 149constant at 34 km/h, determine the change
in acceleration when leaving one arc and
entering the other. [1.49 m/s^2 ]- An object is suspended by a thread
400 mm long and both object and thread
move in a horizontal circle with a constant
angular velocity of 3.0 rad/s. If the tension
in the thread is 36 N, determine the mass
of the object. [10 kg]
13.4 Rotation of a rigid body about a
fixed axis
A rigid body is said to be a body that does not
change its shape or size during motion. Thus, any
two particles on a rigid body will remain the same
distance apart during motion.
Consider the rigidity of Figure 13.4, which is
rotating about the fixed axisO.
OyxatrΔFt= Δm.ar
ΔmaFigure 13.4
In Figure 13.4,
α=the constant angular accelerationm=the mass of a particler=the radius of rotation ofmat=the tangential acceleration ofmFt=the elemental force on the particleNow, forceF=ma
or Ft=mat
=m(αr)Multiplying both sides of the above equation byr,
gives:
Ftr=mαr^2Sinceαis a constant
∑
Ftr=α∑
mr^2or T=Ioα ( 13. 3 )where T=the total turning moment
exerted on the rigid body=∑
FtrandIo=the mass moment of inertia (or second
moment) aboutO(inkgm^2 ).
Equation (13.3) can be seen to be the rotational
equivalent ofF =ma (Newton’s second law of
motion).Problem 11. Determine the angular
acceleration that occurs when a circular disc
of mass moment of inertia of 0.5 kg m^2 is
subjected to a torque of 6 N m. Neglect
friction and other losses.From equation (13.3), torqueT=Iα,
from which,angular acceleration,α=T
I=6Nm
0 .5kgm^2=12 rad/s^213.5 Moment of inertia (I)
The moment of inertia is required for analysing
problems involving the rotation of rigid bodies. It
is defined as:I=mk^2 =mass moment of inertia(kg/m^2 )wherem=the mass of the rigid bodyk=its radius of gyration about the pointof rotation (see Chapter 7).In general,I=∑
mr^2 where the definitions of
Figure 13.1 apply.