FORCE, MASS AND ACCELERATION 149
constant at 34 km/h, determine the change
in acceleration when leaving one arc and
entering the other. [1.49 m/s^2 ]
- An object is suspended by a thread
400 mm long and both object and thread
move in a horizontal circle with a constant
angular velocity of 3.0 rad/s. If the tension
in the thread is 36 N, determine the mass
of the object. [10 kg]
13.4 Rotation of a rigid body about a
fixed axis
A rigid body is said to be a body that does not
change its shape or size during motion. Thus, any
two particles on a rigid body will remain the same
distance apart during motion.
Consider the rigidity of Figure 13.4, which is
rotating about the fixed axisO.
O
y
x
at
r
ΔFt= Δm.ar
Δm
a
Figure 13.4
In Figure 13.4,
α=the constant angular acceleration
m=the mass of a particle
r=the radius of rotation ofm
at=the tangential acceleration ofm
Ft=the elemental force on the particle
Now, forceF=ma
or Ft=mat
=m(αr)
Multiplying both sides of the above equation byr,
gives:
Ftr=mαr^2
Sinceαis a constant
∑
Ftr=α
∑
mr^2
or T=Ioα ( 13. 3 )
where T=the total turning moment
exerted on the rigid body
=
∑
Ftr
andIo=the mass moment of inertia (or second
moment) aboutO(inkgm^2 ).
Equation (13.3) can be seen to be the rotational
equivalent ofF =ma (Newton’s second law of
motion).
Problem 11. Determine the angular
acceleration that occurs when a circular disc
of mass moment of inertia of 0.5 kg m^2 is
subjected to a torque of 6 N m. Neglect
friction and other losses.
From equation (13.3), torqueT=Iα,
from which,angular acceleration,
α=
T
I
=
6Nm
0 .5kgm^2
=12 rad/s^2
13.5 Moment of inertia (I)
The moment of inertia is required for analysing
problems involving the rotation of rigid bodies. It
is defined as:
I=mk^2 =mass moment of inertia(kg/m^2 )
wherem=the mass of the rigid body
k=its radius of gyration about the point
of rotation (see Chapter 7).
In general,I=
∑
mr^2 where the definitions of
Figure 13.1 apply.