17
Simple harmonic motion
At the end of this chapter you should be
able to:
- understand simple harmonic motion
- determine natural frequencies for simple
spring-mass systems - calculate periodic times
- understand the motion of a simple
pendulum - understand the motion of a compound
pendulum
17.1 Introduction
Simple harmonic motion is of importance in a num-
ber of branches of engineering and physics, includ-
ing structural and machine vibrations, alternating
electrical currents, sound waves, light waves, tidal
motion, and so on.
17.2 Simple harmonic motion (SHM)
A particle is said to be under SHM if its accel-
eration along a line is directly proportional to its
displacement along that line, from a fixed point on
that line.
Consider the motion of a particleA, rotating in a
circle with a constant angular velocityω, as shown
in Figure 17.1.
Consider now the vertical displacement ofAfrom
xx, as shown by the distanceyc.IfPis rotating at
a constant angular velocityωthen the periodic time
Tto travel an angular distance of 2π, is given by:
T=
2 π
ω
( 17. 1 )
Letf=frequency of motionC(in Hertz), where
f=
1
T
=
ω
2 π
( 17. 2 )
0
yc
c
y
−y
A
B
vA
vAsinq
vAcosq
w
−xxr
r
q
Displacement (yc)
Accelration (−ac)
Velocity (vc)
time't'
(a) (b)
Figure 17.1
To determine whether or not SHM is taking place,
we will consider motion ofAin the directionyy.
NowyC=OAsinωt,
i.e., yc=rsinωt ( 17. 3 )
wheret=time in seconds.
Plotting of equation (17.3) againsttresults in the
sinusoidal variation for displacement, as shown in
Figure 17.1(b).
From Chapter 11,vA = ωr, which is the tan-
gential velocity of the particleA. From the veloc-
ity vector diagram, at the pointAon the circle of
Figure 17.1(a),
vC=vAcosθ=vAcosωt ( 17. 4 )
Plotting of equation (17.4) againsttresults in the
sinusoidal variation for the velocityvC, as shown in
Figure 17.1(b).
The centripetal acceleration ofA
=aA=ω^2 r
Now aC=−aAsinθ
Therefore, aC=−ω^2 rsinωt ( 17. 5 )
Plotting of equation (17.5) againsttresults in the
sinusoidal variation for the acceleration atC,aC,as
shown in Figure 17.1(b).
Substituting equation (17.3) into equation (17.5)
gives:
aC=−ω^2 yC ( 17. 6 )