17
Simple harmonic motion
At the end of this chapter you should be
able to:- understand simple harmonic motion
- determine natural frequencies for simple
spring-mass systems - calculate periodic times
- understand the motion of a simple
pendulum - understand the motion of a compound
pendulum
17.1 Introduction
Simple harmonic motion is of importance in a num-
ber of branches of engineering and physics, includ-
ing structural and machine vibrations, alternating
electrical currents, sound waves, light waves, tidal
motion, and so on.
17.2 Simple harmonic motion (SHM)
A particle is said to be under SHM if its accel-
eration along a line is directly proportional to its
displacement along that line, from a fixed point on
that line.
Consider the motion of a particleA, rotating in a
circle with a constant angular velocityω, as shown
in Figure 17.1.
Consider now the vertical displacement ofAfrom
xx, as shown by the distanceyc.IfPis rotating at
a constant angular velocityωthen the periodic time
Tto travel an angular distance of 2π, is given by:
T=2 π
ω( 17. 1 )Letf=frequency of motionC(in Hertz), where
f=1
T=ω
2 π( 17. 2 )0yccy−yABvAvAsinq
vAcosqw−xxrr
qDisplacement (yc)
Accelration (−ac)
Velocity (vc)time't'(a) (b)Figure 17.1To determine whether or not SHM is taking place,
we will consider motion ofAin the directionyy.
NowyC=OAsinωt,i.e., yc=rsinωt ( 17. 3 )wheret=time in seconds.
Plotting of equation (17.3) againsttresults in the
sinusoidal variation for displacement, as shown in
Figure 17.1(b).
From Chapter 11,vA = ωr, which is the tan-
gential velocity of the particleA. From the veloc-
ity vector diagram, at the pointAon the circle of
Figure 17.1(a),vC=vAcosθ=vAcosωt ( 17. 4 )Plotting of equation (17.4) againsttresults in the
sinusoidal variation for the velocityvC, as shown in
Figure 17.1(b).
The centripetal acceleration ofA=aA=ω^2 rNow aC=−aAsinθTherefore, aC=−ω^2 rsinωt ( 17. 5 )Plotting of equation (17.5) againsttresults in the
sinusoidal variation for the acceleration atC,aC,as
shown in Figure 17.1(b).
Substituting equation (17.3) into equation (17.5)
gives:aC=−ω^2 yC ( 17. 6 )