THE EFFECTS OF FORCES ON MATERIALS 13Therefore, drop in thermal strain=− 30 × 106 Pa
2 × 1011 Pa=− 1. 5 × 10 −^4 =αTfrom which, temperatureT=− 1. 5 × 10 −^4
14 × 10 −^6=− 10. 7 °CHence, the drop in temperatureT from 20°C
is−10.7°C
Therefore,the temperature for the prop to
be ineffective= 20 °− 10. 7 °= 9. 3 °CNow try the following exerciseExercise 4 Further problem on thermal
strain- A steel rail may assumed to be stress
free at 5°C. If the stress required to cause
buckling of the rail is−50 MPa, at what
temperature will the rail buckle?. It may
be assumed that the rail is rigidly fixed at
its ‘ends’.
TakeE= 2 × 1011 N/m^2 and
α= 14 × 10 −^6 /°C. [22.86°C]
1.12 Compound bars
Compound bars are of much importance in a num-
ber of different branches of engineering, including
reinforced concrete pillars, composites, bimetallic
bars, and so on. In this section, solution of such
problems usually involve two important considera-
tions, namely(a) compatibility
(or considerations of displacements)(b) equilibrium
N.B. It is necessary to introduce compatibility in
this section as compound bars are, in general, stat-
ically indeterminate (see Chapter 4). The follow-
ing worked problems demonstrate the method of
solution.Problem 19. A solid bar of cross-sectional
areaA 1 , Young’s modulusE 1 and coefficient
of linear expansionα 1 is surrounded
co-axially by a hollow tube of cross-sectional
areaA 2 , Young’s modulusE 2 and coefficient
of linear expansionα 2 , as shown in
Figure 1.12. If the two bars are secured
firmly to each other, so that no slipping takes
place with temperature change, determine the
thermal stresses due to a temperature riseT.
Both bars have an initial lengthLand
α 1 >α 2BarL1
Bar 2Figure 1.12 Compound barα 1 LTL α 2 LTε 1 Lε 2 LAABar 1Bar 2Figure 1.13 “Deflections” of compound barThere are two unknown forces in these bars, namely
F 1 andF 2 ; therefore, two simultaneous equations
will be required to determine these unknown forces.
The first equation can be obtained by considering
the compatibility (i.e.‘deflections’) of the bars, with
the aid of Figure 1.13.Free expansion of bar (1)=α 1 LTFree expansion of bar (2)=α 2 LTIn practice, however, the final resting position of
the compound bar will be somewhere in between