Mechanical Engineering Principles

(Dana P.) #1

6


Bending moment and shear force


diagrams


At the end of this chapter you should be
able to:


  • define a rigid-jointed framework

  • define bending moment

  • define sagging and hogging

  • define shearing force

  • calculate bending moments

  • calculate shearing forces

  • plot bending moment diagrams

  • plot shearing force diagrams

  • define the point of contraflexure


6.1 Introduction


The members of the structures in Chapter 4 with-
stood the externally applied loads in either tension
or compression; this was because they were not sub-
jected to bending.
In practise many structures are subjected to bend-
ing action; such structures include beams and rigid-
jointed frameworks. A rigid-jointed framework is
one which has its joints welded or riveted or bolted
together; such structures are beyond the scope of
this text (see reference [1], on page 54). Prior to
calculating bending moments and shearing forces,
we will first need to define bending moment and
shearing force.


6.2 Bending moment (M)


The units of bending moment are N mm, N m,
kN m, etc. When a beam is subjected to the couples


(a) Sagging moment (+) (b) Hogging moment (−)

MMMM

Figure 6.1 Bending moments

shown in Figure 6.1, the beam will suffer flexure
due to the bending moment of magnitudeM.
If the beam is in equilibrium and it is subjected to
a clockwise couple of magnitudeMon the left of
the section, then from equilibrium considerations,
the couple on the right of the section will be of
exactly equal magnitude and of opposite direction
to the couple on the left of the section. Thus, when
calculating the bending moment at a particular point
on a beam in equilibrium, we need only calculate
the magnitude of the resultant of all the couples on
one side of the beam under consideration. This is
because as the beam is in equilibrium, the magnitude
of the resultant of all the couples on the other side
of the beam is exactly equal and opposite. The beam
in Figure 6.1(a) is said to besaggingand the beam
inFigure6.1(b)issaidtobehogging.
Thesign conventionadopted in this text is:

(a) sagging momentsare said to bepositive

(b) hogging momentsare said to benegative

6.3 Shearing force (F)


Whereas a beam can fail due to its bending moments
being excessive, it can also fail due to other forces
being too large, namely the shearing forces; these
are shown in Figure 6.2. The units of shearing force
areN,kN,MN,etc.
It can be seen from Figures 6.2(a) and (b) that the
shearing forcesF act in a manner similar to that
exerted by a pair of garden shears when they are
used to cut a branch of a shrub or a plant through
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