Solutions
- ,IWKHVLGHVRIWKHUHFWDQJOHFRPHLQDUDWLRWKHQWKHVLGHOHQJWKV
are 4x and 3x for some value x, as shown in Figure S.5.3.
:HKDYHWKHIROORZLQJ
.
xx
xx
x
x
x
6RWKHOHQJWKDQGZLGWKRIWKHUHFWDQJOHDUH^63 and^84.
- Label the remaining side h, as shown in Figure S.5.4.
Dͽ %\WKH3\WKDJRUHDQWKHRUHP
9
9 more
9
3.
ah
a
a
a
!
!
Eͽ %\WKH3\WKDJRUHDQWKHRUHP
bh
b
b
!
!
Fͽ b h, which is obviously larger than 9 + h = aͼEHFDXVHLVODUJHUWKDQͽ
Thus, b! a. This gives b! a.
h a b
32
Figure S.5.4
4 x
3 x^21
Figure S.5.3