Samples: Free-Response Questions
- The reaction
2 NO 2 (g) + Cl 2 (g) →2 NO 2 Cl(g)
was studied at 20°C and the following data were obtained:
Experiment Initial [NO 2 ] Initial [Cl 2 ] Initial Rate of Increase
(mole ⋅ liter–1) (mole ⋅ liter–1) of [NO 2 Cl]
(mole ⋅liter–1⋅sec–1)
1 0.100 0.005 1.35 × 10 –7
2 0.100 0.010 2.70 × 10 –7
3 0.200 0.010 5.40 × 10 –7
(a) Write the rate law for the reaction.
(b) What is the overall order for the reaction? Explain.
(c) Calculate the rate-specific constant, including units.
(d) In Experiment 3, what is the initial rate of decrease of [Cl 2 ]?
(e) Propose a mechanism for the reaction that is consistent with the rate law expression
you found in part (a).
Answer
- Given: 2 NO 2 (g) + CO 2 (g) →2 NO 2 Cl(g)
(a) Restatement: Rate law.
rate = k[NO 2 ]n[Cl 2 ]m
Expt. 1: rate = 1.35 × 10 –7mole/liter ⋅sec
= k(0.100 M)n(0.0050 M)m
Expt. 2: rate = 2.70 × 10 –7mole/liter ⋅sec
= k(0.100 M)n(0.010 M)m
Expt. 3: rate = 5.40 × 10 –7mole/liter ⋅sec
= k(0.200 M)n(0.010 M)m
./
./
1
2
135 10
270 10
rate
rate
mole liter sec
mole liter sec
7
7
#:
= #:
..
..
k
k
0 100 0 0050
0 100 0 010
MM
MM
nm
nm
=
^^
^^
hh
hh
= 2.00 = (2.0)mm= 1
Kinetics