Step 1: Write the net cell reaction.
Ag(s) + Au+(aq) EAg+(aq) + Au(s)
Step 2: Write the two half-reactions and include the E°redand E°oxvalues.
:
:
ox Ag Ag e
red Au e Au
Ag Au Ag Au
saq
aq s
saq aqs
E
E
E
+
++
+-+
+-
++
^ _
_ ^
^ __^
h i
i h
h iih
.
.
.
E volt
E volts
E volt
0 7991
168
088
ox
red
=-
=
=+
%
%
%
Because the sign of E°is positive, the reaction will proceed spontaneously.
3.... FeCl 2 +... KMnO 4 +... HCl →... FeCl 3 +... KCl +... MnCl 2 +? H 2 O
When the equation for this reaction is balanced with the lowest whole-number
coefficients, the coefficient for H 2 O is
A. 1
B. 2
C. 3
D. 4
E. 5
Answer:D
Step 1:Decide what elements are undergoing oxidation and what elements are undergoing
reduction.
ox: Fe2+"Fe3+
red: MnO 4 - "Mn^2 +
Step 2: Balance each half-reaction with respect to atoms and then charges.
ox: Fe2+"Fe3++ e–
Balance the reduction half-reaction, using water to balance the O’s.
red: MnO 4 - "Mn^2 ++ 4 HO 2
Balance the H atoms with H+ions.
red: MnO 4 - + 8 H+"Mn^2 ++ 4 HO 2
Part II: Specific Topics