- Calculate the mass of NH 3 in the Ni(NH 3 )nCl 2 sample.
..
.
mol NH
mol NHgNH
1 gNH0 00329 17 04
1 3 0 0561^33
3
# =- Calculate the mass percent of NH 3 in Ni(NH 3 )nCl 2.
n%.%
..
gNi NH ClgNH
100 43 2
0 1300 0561
32
==^3 #
^hMass Percent of Ni2+in Ni(NH 3 )nCl 2
Recap: 50. mL samples of known concentration of [Ni(NH 3 )n]2+were made up byusing NiSO 4 ⋅6 H 2 O. The concentrations were then plotted versus their absorbance.
The unknown solution’s absorbance was then extrapolated from this graph and used
in the calculation for the mass percent of Ni2+.7. Calculate the number of moles of NiSO 4 ⋅6 H 2 O added to form the standard solution.
.
.g NiSO H O
g NiSO H Omol NiSO H O
10 3000
262 88(^61)
6
(^426)
42
: # 42
:
: = 0.0041 mol of NiSO
4 ⋅6 H 2 O
- Calculate the number of moles of Ni(NH 3 )nCl 2 in the standard solution.
. mol of NiSO H O
mol of NiSO H O
mol Ni NH Cl
10 001141
16 1
6(^42) n
42
32
| : |
|---|
| ^h |
| = 0.001141 mol Ni(NH 3 )nCl 2 |
- Calculate the concentration of Ni(NH 3 )nCl 2 in the standard solution.
...
mL.
mol Ni NH Cl
LmL
50 0 M0 001141
11000
n 0 0228
32
# =^h- Calculate the absorbance of the standard (known) and unknown solutions of
[Ni(NH 3 )n]2+from their measured transmittance.
absorbance of standard solution = 2.000 – log (32.6) = 0.487
absorbance of unknown solution of Ni(NH 3 )nCl 2 = 2.000 – log (22.4) = 0.650 - Calculate the concentration of the unknown solution of Ni(NH 3 )nCl 2 , given that
cA b
c
ε A
ss
syn
==syn
where As= absorbance of [Ni(NH 3 )n]2+from standard solution, Asyn= absorbance of
[Ni(NH 3 )n]2+from synthesized Ni(NH 3 )nCl 2 , cs= concentrations of standard solution
and csyn= concentrations of synthesized solution.
..
L..mol M
10 650 0 0228
0 487
##^1 =0 0304- Calculate the concentration of the Ni2+(aq)ion in the unknown solution.
.
L.
mol Ni NH Cl
mol Ni NH Cl0 0304 mol Ni M
1n (^1) 0 0304
n
32
32
2
=
^ +
^
h
h
- Calculate the mass of Ni2+(aq)ion in 50.0 mL of the unknown solution.
.. .'
L
mol Ni
mol NigNi mL sol n
mL0 0304 L
158 69
150 0
1000(^21)
2
2
###= 0.0892 g Ni2+
Part III: AP Chemistry Laboratory Experiments