Cliffs AP Chemistry, 3rd Edition

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Next, the student used three different combinations of metals for both anodes and cathodes and
measured the potential difference. The results are presented in Table 5.


Table 5
Anode Cathode Measured Potential Difference
Fe Cu 0.50
Mg Pb 1.00
Pb Cu 0.51

A 0.0100 M Cu(NO 3 ) 2 solution was then made up and used in the Cu2+| Cu half-cell. The
[Zn2+(aq)] was kept at 1.0 M in the Zn | Zn2+half-cell. The voltage was then determined and mea-
sured as 1.01 volts.


The student then added 10. mL of 1.0 M NaCl solution to an empty beaker. He then added one
drop of 1.0 M AgNO 3 to the beaker and stirred well. Since there is an abundance of Cl−in the
beaker, and the amount of NaCl (10. mL) is magnitudes greater than the one drop of 1.0 M
AgNO 3 , it can be assumed that most of the Ag+(aq)will combine with the Cl–(aq)and that the con-
centration of the Cl–(aq)will remain essentially 1.0 M. A silver metal electrode was immersed in
this solution and connected through the salt bridge to the Zn | Zn2+half-cell. The potential dif-
ference was measured as 0.91 volts.


And finally, the same procedure was followed as above, but instead of obtaining an unknown
concentration of silver ion, the student prepared a solution containing 2 drops of 1.00 M
Cu(NO 3 ) 2 in 10. mL of 6.00 M NH 3. The student determined that it took 20. drops to equal 1
mL. This solution was then added to the cell containing the copper electrode. The voltage was
read as 0.56 V. The cell can be represented as:


Zn(s)| Zn2+(aq)(1.00 M) || Cu2+(aq)(? M) | Cu(s)

Analysis:



  1. Examine Table 1. Write balanced net ionic equations where reactions occurred and iden-
    tify the oxidizing agent (OA) and the reducing agent (RA) for each equation.
    Cu^22 +()aq +Mg()ss"Cu()+Mg()aq+ OA = Cu2+; RA = Mg(s)
    Cu^22 +()aq +Pb()ss"Cu()+Pb()aq+ OA = Cu2+; RA = Pb(s)
    Cu^22 +()aq +Zn()ss"Cu()+Zn()aq+ OA = Cu2+; RA = Zn(s)
    Pb^22 +()aq +Mg()ss"Pb()+Mg()aq+ OA = Pb2+; RA = Mg(s)

  2. Referring to Table 1, list the metals studied in order of increasing ease of oxidation.
    Copper < Lead < Magnesium

  3. Referring to Table 1, list the metallic ions studied in order of increasing ease of reduction.
    Mg2+(aq) < Pb2+(aq) < Cu2+(aq)


Part III: AP Chemistry Laboratory Experiments

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