The Keqis needed for the following equation:
.
.
() () () ()
.
AgCl s I aq AgI s Cl aq K
I
Cl
L
mole
mole
16 10 L
10
20 10
80
eq
2
10 2
17 2
2
6
"
#
#
#
= #
++ =
--
7
7
A
A
- (D)
Bond breaking (∆H 1 ) = HH + FF = 103 kcal ⋅mole–1+ 33 kcal ⋅mole–1
= 136 kcal ⋅mole–1
Bond forming (∆H 2 ) = 2 HF = 2(−135 kcal ⋅mole–1) = –270 kcal ⋅mole–1
∆H°= ∆H 1 + ∆H 2 = 136 kcal ⋅mole–1+ (−270 kcal ⋅mole–1) = −134 kcal/mole
- (D) Whether you can answer this question depends on whether you are acquainted with
what is known as the Maxwell-Boltzmann distribution. This distribution describes the way
that molecular speeds or energies are shared among the molecules of a gas. If you missed
this question, examine the following figure and refer to your textbook for a complete de-
scription of the Maxwell-Boltzmann distribution.
- (A) Because all choices have 18 electrons in their valence shell, you should pick the
species with the fewest protons in the nucleus; this would result in the weakest electrosta-
tic attraction. That species is sulfur.
- (A) The central metal ion forms only two bonds to ligands, so the coordination number is 2.
- (C) The body-centered cubic cell looks like this:
number ofmolecules
molecular speed
500 °C
0 °C
Answers and Explanations for the Practice Test