∆Hreaction= −qwater
gC gC
specific heat of water^418. J^1 cal
::
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∆H°= ΣH°f products−ΣH°f reactants= qp
where qp= heat flow, constant p
1 calorie = 4.184 Joules
101 Joules = 1 liter ⋅atm
24.14 calories = 1 liter ⋅atm
- law of Dulong and Petit
molar mass ⋅specific heat ≈25 J/mole ⋅°C
- first law of thermodynamics
∆E= q+ w= qp−P∆V= ∆H−P∆V
In any process, the total change in energy of the system, ∆E, is equal to the sum of the
heat absorbed, q, and the work, w, done on the system.
- second law of thermodynamics
∆Suniv= ∆Ssys+ ∆Ssurr> 0 spontaneous
∆Suniv= ∆Ssys+ ∆Ssurr< 0 nonspontaneous
∆Suniv= ∆Ssys+ ∆Ssurr= 0 equilibrium
The entropy of the universe increases in a spontaneous process and remains unchanged in
an equilibrium process.
- third law of thermodynamics
S°= qp/ T
∆S°= ΣS°products−ΣS°reactants
The entropy of a perfect crystalline substance is zero at absolute zero.
- Hess’s law: If reaction (1) has ∆H 1 and reaction (2) has ∆H 2 and reaction (1) +
reaction (2) = reaction (3), then
∆H 3 = ∆H 1 + ∆H 2 - Bond breaking: potential energy (enthalpy) of bond is increased; “strong” bonds →
“weak” bonds; ∆H > 0.
Bond forming: potential energy (enthalpy) of bond is decreased; bond distance is de-
creased; “weak” bonds →“strong” bonds; ∆H< 0.
∆H= Σbond energy (reactants) −Σbond energy (products) = total energy input −total
energy released
Thermochemistry