Answer: C
First, the ice must be heated to its melting point, 0.0°C.
(mass) ×(specific heat capacity) ×(∆t)
: C
...
.
(^1) g
10 0 0 500
1
10 0
50 0
g ice cal C
##% = cal
%
Next, the ice must be melted.
(mass) ×(∆Hfus)
..
1 g
10 0 76 4
764
g ice cal
# = cal
Next, the water must be heated to its boiling point, 100.0°C.
gC:
..
.
C
1
10 0 100
1 100 10
g water cal
###% =^3 cal
100 0.%
Next, the water must be vaporized.
. g water
g
cal cal
1
10 0 539
# = 5390
Next, the steam must be heated to 150.0°C
gC:
.. .C
1
10 0 0 482
1
50 0
241
g stream cal
##% = cal
%
The last step is to add up all quantities of heat required.
50.0 cal + 764 cal + 1000 cal + 5390 cal + 241 cal = 7445 calories
- Given these two standard enthalpies of formation:
Reaction (1) SO SO^sg gh+ (^22) iiE ∆H°= −295 kJ/mole
Reaction (2) SOSO^sggh+ 32 / 2 iiE 3 ∆H°= −395 kJ/mole
What is the reaction heat for 22 SO 22 ___ggiii+O E SO 3 gunder the same conditions?
A. −1380 kJ/mole
B. −690. kJ/mole
C. −295 kJ/mole
D. −200. kJ/mole
E. −100. kJ/mole
Part II: Specific Topics