Worked Example 11.1
A navigation lock, 200 m12 m in plan and with a 9.00 m head, is filled
through two longitudinal conduits with rectangular gates 3.00 m wide con-
trolling the flow. The overall coefficient of discharge of the filling system is
0.65 and the gates open 8.5 mm s^1 at a uniform speed in 4.5 min. Deter-
mine the maximum discharge entering the lock and the total time of filling.
Solution
The time of opening of the gates is T4.5 60 270 s. The flow area of a
fully open gate is 30.0085 270 6.885 m^2. The flow area of the filling
system is 26.88513.77 m^2. From equation (11.14), for a linear opening
of the filling system the total time of filling is
T
27
2
0
496 s.The head on the lock at the end of the opening of the gates, hT 1 , is from
equation (11.13)
270
4 A
c(H
a(1
2/2
g
)1/h
21/2
T^1 ).ThushT 1 3.55 m. Qmaxoccurs at either hT 1 or 4/9H, whichever is greater;
in this case 4/9H4/9 9 4m3.55 m.
The time at which h4 m can be obtained from the equation
t0tdt
htH (H1/2 ht1/2)t^2 /2;forht4m
t^2 ( 9
4
)65 370 s^2.Thust256 s (270 s) and the maximum discharge occurs before the
filling system is fully open. At time t256 s, the area of opening of the
system is (13.77256)/27013.056 m^2. Therefore (from equation (11.9b))
Qmax0.6513.056(419.6)1/275.19 m^3 s^1.
4 200 12 270
0.6513.77 1
9
.6
22 AT 1
ca(2g)1/2dh
h1/2AT 1
ca(2g)1/24 200 12(3 h1/2T 1 )
0.6513.77 1
9
.6
22 200 (^129)
0.6513.77 1
9
.6
2
2 AH1/2
ca(2g)1/2T 1
2