CK-12 Geometry Concepts

(Elliott) #1

1.4. Midpoints and Segment Bisectors http://www.ck12.org


Guided Practice



  1. Which line is the perpendicular bisector ofMN?

  2. Findxandy.

  3. Find the midpoint between (3, 7) and (7, 11)


Answers:



  1. The perpendicular bisector must bisectMNand be perpendicular to it. Only


←→


OQsatisfies both requirements.

←→


SR


is just a bisector.




  1. The line shown is the perpendicular bisector. So, 3x− 6 = 21 , 3 x= 27 ,x=9. And,( 4 y− 2 )◦= 90 ◦, 4 y◦=
    92 ◦,y= 23 ◦.




  2. (
    3 + 7
    2




,


7 + 11


2


)


=


(


10


2


,


18


2


)


= ( 5 , 9 )


.


Practice



  1. Copy the figure below and label it with the following information:


(^6) A∼= (^6) C
(^6) B∼= (^6) D
AB∼=CD
AD∼=BC
For 2-9, find the lengths, given:His the midpoint ofAEandDG,Bis the midpoint ofAC,GDis the perpendicular
bisector ofFAandEC,AC∼=F E,andFA∼=EC.


2.AB


3.GA


4.ED


5.HE


6.FA


7.GD



  1. How many copies of triangleAHBcan fit inside rectangleF ECAwithout overlapping?
    9.ConstructionUsing your ruler, draw a line segment that is 7 cm long. Then use your compass to construct
    the perpendicular bisector, What is the measure of each segment?
    10.ConstructionUsing your ruler, draw a line segment that is 4 in long. Then use your compass to construct the
    perpendicular bisector, What is the measure of each segment?


For questions 10-13, find the midpoint between each pair of points.



  1. (-2, -3) and (8, -7)

  2. (9, -1) and (-6, -11)

  3. (-4, 10) and (14, 0)

  4. (0, -5) and (-9, 9)

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