CK-12 Geometry Concepts

(Elliott) #1

http://www.ck12.org Chapter 10. Perimeter and Area


( 8 + 24 )^2 + 152 =h^2
h^2 = 1249
h≈ 35. 3 in

The perimeter is 24+ 35. 3 + 17 ≈ 76. 3 in.



  1. The area is^12 ( 24 )( 15 ) = 180 in^2.


Practice


Use the triangle to answer the following questions.



  1. Find the height of the triangle by using the geometric mean.

  2. Find the perimeter.

  3. Find the area.


Find the area of the following shape.


4.


  1. What is the height of a triangle with area 144m^2 and a base of 24 m?


For problems 6 and 7 find the height and area of the equilateral triangle with the given perimeter.



  1. Perimeter 18 units.

  2. Perimeter 30 units.

  3. Generalize your results from problems 6 and 7 into a formula to find the height and area of an equilateral
    triangle with side lengthx.


Find the area of each triangle.



  1. Find the area of a triangle with a base of 10 in and a height of 12 in.

  2. Find the area of a triangle with a base of 5 in and a height of 3 in.

  3. An equilateral triangle with a height of 6



3 units.


  1. A 45-45-90 triangle with a hypotenuse of 5



2 units.


  1. A 45-45-90 triangle with a leg of 12 units.

  2. A 30-60-90 triangle with a hypotenuse of 24 units.

  3. A 30-60-90 triangle with a short leg of 5 units.

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