Quantum Mechanics for Mathematicians

(lily) #1

The pair (V,J) can be thought of as givingVthe structure of a complex vector
space, withJproviding multiplication byi. Similarly, taking


v∈V→

1


2

(v+iJv)∈VJ− (26.2)

identifiesVwithVJ−, withJnow providing multiplication by−i.VJ+andVJ−
are interchanged by changing the complex structureJto−J.
For the study of quantization, the real vector space we want to choose a
complex structure on is the dual phase spaceM=M∗, since it is elements of this
space that are in a Heisenberg algebra, and taken to operators by quantization.
There will be a decomposition


M⊗C=M+J⊕M−J

and quantization will take elements ofM+J to linear combinations of creation
operators, elements ofM−J to linear combinations of annihilation operators.
The standard choice of complex structure is to takeJ=J 0 , whereJ 0 is the
linear operator that acts on coordinate basis vectorsqj,pjofMby


J 0 qj=pj, J 0 pj=−qj

Making the choice


zj=

1


2

(qj−ipj)

implies


J 0 zj=

1


2

(pj+iqj) =izj

and thezjare basis elements (over the complex numbers) ofM+J 0. The complex
conjugates


zj=

1


2

(qj+ipj)

provide basis elements ofM−J 0
With respect to the chosen basisqj,pj, the complex structure can be written
as a matrix. For the case ofJ 0 and ford= 1, on an arbitrary element ofMthe
action ofJ 0 is
J 0 (cqq+cpp) =cqp−cpq


soJ 0 in matrix form with respect to the basis (q,p) is


J 0

(

cq
cp

)

=

(

0 − 1

1 0

)(

cq
cp

)

=

(

−cp
cq

)

(26.3)

or, the action on basis vectors is the transpose


J 0

(

q
p

)

=

(

0 1

−1 0

)(

q
p

)

=

(

p
−q

)

(26.4)

Note that, after complexifying, three different ways to identify the original
Mwith a subspace ofM⊗Care:

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