Definition(Lie bracket). The Lie bracket operation ongis the bilinear anti-
symmetric map given by the commutator of matrices
[·,·] : (X,Y)∈g×g→[X,Y] =XY−Y X∈g
We need to check that this is well-defined, i.e., that it takes values ing.
Theorem.IfX,Y∈g,[X,Y] =XY−Y X∈g.
Proof.SinceX∈g, we haveetX∈Gand we can act onY∈gby the adjoint
representation
Ad(etX)Y=etXY e−tX∈g
Astvaries this gives us a parametrized curve ing. Its velocity vector will also
be ing, so
d
dt
(etXY e−tX)∈g
One has (by the product rule, which can easily be shown to apply in this case)
d
dt
(etXY e−tX) =
(
d
dt
(etXY)
)
e−tX+etXY
(
d
dt
e−tX
)
=XetXY e−tX−etXY Xe−tX
Evaluating this att= 0 gives
XY−Y X
which is thus, from the definition, shown to be ing.
The relation
d
dt
(etXY e−tX)|t=0= [X,Y] (5.1)
used in this proof will be continually useful in relating Lie groups and Lie alge-
bras.
To do calculations with a Lie algebra, one can choose a basisX 1 ,X 2 ,...,Xn
for the vector spaceg, and use the fact that the Lie bracket can be written in
terms of this basis as
[Xj,Xk] =
∑n
l=1
cjklXl (5.2)
wherecjklis a set of constants known as the “structure constants” of the Lie
algebra. For example, in the case ofsu(2), the Lie algebra ofSU(2) has a basis
X 1 ,X 2 ,X 3 satisfying
[Xj,Xk] =
∑^3
l=1
jklXl
(see equation 3.5) so the structure constants ofsu(2) are the totally antisym-
metricjkl.