DHARM
378 GEOTECHNICAL ENGINEERING
B
q/unit area
L
1
2
1
2
szav
(B+z)
Fig. 10.21 Two is to one method
10.9 ILLUSTRATIVE EXAMPLES
Example 10.1: A concentrated load of 22.5 kN acts on the surface of a homogeneous soil mass
of large extent. Find the stress intensity at a depth of 15 meters and (i) directly under the load,
and (ii) at a horizontal distance of 7.5 metres. Use Boussinesq’s equations.
(S.V.U.—B.E., (R.R.)—Dec., 1970)
According to Boussinesq’s theory,
σz =
Q
zrz^2252
32
1
.
(/ )
[(/)]/
π
+
(i) Directly under the load:
r = 0. ∴ r/z = 0
z = 15 m Q = 22.5 kN
∴σz =
22 5
15 15
32
1052
. .(/ )
× ()+ /
π
= 47.75 kN/m^2.
(ii) At a horizontal distance of 7.5 metres:
r = 7.5 m z = 15 m
r/z = 7.5/15 = 0.5
∴ σz =
22 50
15 15
32
105252
.
.
(/ )
× [( +(. ) ]/
π
= 27.33 N/m^2.