DHARM
48 GEOTECHNICAL ENGINEERING
3.8.3 Sedimentation Analysis (Wet Analysis)
The soil particles less than 75–μ size can be further analysed for the distribution of the various
grain-sizes of the order of silt and clay be ‘sedimentation analysis’ or ‘wet analysis’. The soil
fraction is kept in suspension in a liquid medium, usually water. The particles descend at
velocities, related to their sizes, among other things.
The analysis is based on ‘Stokes Law’ for what is known as the ‘terminal velocity’ of a
sphere falling through an infinite liquid medium. If a single sphere is allowed to fall in an
infinite liquid medium without interference, its velocity first increases under the influence of
gravity, but soon attains a constant value. This constant velocity, which is maintained indefi-
nitely unless the boundary conditions change, is known as the ‘terminal velocity’. The princi-
ple is obvious; coarser particles tend to settle faster than finer ones.
By Stokes’ law, the terminal velocity of the spherical particle is given by
v = (1/18). [(γs – γτ)/μτ]. D^2 ...(Eq. 3.16)
which is dimensionally consistent.
Thus, if
γs = unit weight of the material of falling sphere in g/cm^3 ,
γτ = unit weight of the liquid medium in g/cm^3 ,
μτ = viscosity of the liquid medium in g sec/cm^2 ,
and D = diameter of the spherical particle in cm,
v, the terminal velocity, is obtained in cm/s.
In S.I. units,
if γs and γτ are expressed in kN/m^3 ,
μ 1 in kN sec/m^2 ,
D in metres,
v will be obtained in m/sec.
Since, usually D is to be expressed in mm, while v is to be expressed in cm/sec, an μτ in
N-sec/m^2 , Eq. 3.15 may be rewritten as follows:
v =
1
180
()γγ. 2
μ
τ
τ
s− D ...(Eq. 3.17)
Here γs and γτ are in kN/m^3 , μτ in N-sec/m^2 , and D in mm; v will then be in cm/sec.
Usually, the liquid medium is water; then γτ and μτ will be substituted by γw and μw. Then
Eq. 3.16 will become:
v =
1
180
()γγ. 2
μ
sw
w
− D ...(Eq. 3.18)
It should be noted that γw and μw vary with temperature, the latter varying more signifi-
cantly than the former.
Noting that γs = G.γw ,
v =
1
180
.γ ()^1.^2
μ
w
w
G− D
...(Eq. 3.19)
At 20°C, γw = 0.9982 g/cm^3 = 0.9982 × 9.810 kN/m^3
= 9.792 kN/m^3
μw = 0.001 N-sec/m^2